Velocity
Average Velocity
Therefore, the total displacement covered by the airplane during its entire flight was
d1 + d2 = 1050 km + 1000 km
=2050km.
Its total time is
t1 + t2 = 3 h + 2.5 h
= 5.5 h.
The average velocity then is
\[
\begin{aligned}
v &= \frac{\overrightarrow{d}}{t} \\
&= \frac{2050\, \text{km}}{5.5\, \text{h}} \\
&= 372.73\, \text{km/h}
\end{aligned}
\]
